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p.m. and A patient's temperature was recorded at 8 a.m., 10 a.m., 4 6 p.m. The first, second, and fourth readings were 65° F, 85° F and 90° F, respectively. If the average of the four readings was 80° F, what was the third reading?

Respuesta :

Answer:

The value of the third reading is 80 F

[tex]x=80^0F[/tex]

Explanation:

Let x represent the value of the third reading.

The average of a set of data equals the sum of all the data divided by the number of data;

[tex]\text{Average =}\frac{sum\text{ of data}}{\text{number of data}}[/tex]

Given;

Average = 80 F

Sum of data = 65+85+x+90

Number of data = 4

substituting we have;

[tex]80=\frac{65+85+x+90}{4}[/tex]

solving for x;

[tex]\begin{gathered} 80=\frac{65+85+x+90}{4} \\ 80\times4=65+85+x+90 \\ 320=65+85+x+90 \\ 320=240+x \\ 320-240=x \\ x=80 \end{gathered}[/tex]

Therefore, The value of the third reading is 80 F

[tex]x=80^0F[/tex]

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