Step 1
Given:
The average weight of a bag of popcorn - 3.05 oz
allowable deviation - 0.02 oz
Ave. weight of a bag of potato chips - 5.05 oz
allowable deviation - 0.03 oz
Actual weight of the bag of popcorn - 3.02 oz
Actual weight of the bag of potato chips - 5.02 oz
Step 2
Find the z-score of popcorn
[tex]z=\frac{3.02-3.05}{0.02}=-1.5[/tex]Find the z-score of potato chips
[tex]z=\frac{5.02-5.05}{0.03}=-1[/tex]Thus the answer will be;