In class total nmber of students is n(T) = 38.
The number of students with three or more than three siblings are
[tex]\begin{gathered} n(\ge3)=3+1+0+1 \\ =5 \end{gathered}[/tex]
Determine the probability for the students with three or more than three siblings.
[tex]\begin{gathered} P(\ge3)=\frac{n(\ge3)}{n(T)} \\ =\frac{5}{38} \\ =0.13157 \\ \approx0.132 \end{gathered}[/tex]
Thus answer is 5/38 or 0.132.
