The enthalpy of combustion per mole is -5397.7 kJ/mol.
What is combustion?
The term combustion refers to a reaction in which a substance is burnt in oxygen. Now we know that octane is a hydrocarbon and its combustion follows the general equation for the combustion of hydrocarbons.
[tex]2C_{8}H_{18} (g) + 25O_{2} (g)---- > 16CO_{2} (g) + 18H_{2} O(g)[/tex]
Given that the number of moles in one gram of octane is obtained from;
1g/114 g/mol = 0.0088 moles
If the burning of 0.0088 moles of octane produces -47.5 kJ
Burning of 1 mole of octane would produce 1 mole * -47.5 kJ/0.0088 moles
= -5397.7 kJ/mol
We can now write is as;
[tex]2C_{8}H_{18} (g) + 25O_{2} (g)---- > 16CO_{2} (g) + 18H_{2} O(g)[/tex] ΔH = -5397.7 kJ/mol
Learn more about combustion:https://brainly.com/question/15117038
#SPJ1
