The lengths of AB and CD are 12 and 26.5 units
The given parameters are
AB = 2x + 3
BC = 21
CD = 7x - 5
AD = 11x + 10
The points are on line AD
So, we have
AD = AB + BC + CD
This gives
11x + 10 = 2x + 3 + 21 + 7x - 5
Evaluate the like terms
2x = 9
Divide by 2
x = 4.5
Substitute x = 4.5 in AB = 2x + 3 and CD = 7x - 5
AB = 2 * 4.5 + 3 = 12
CD = 7 * 4.5 - 5 = 26.5
Hence, the lengths of AB and CD are 12 and 26.5 units
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