The electric filed is 2 * 10^-5 N/C.
We know that the electric field is exerted on one charge due to the presence of another charge. Now we are asked to find the electric filed that exists between the charges 10.8 nc and 51.9 nc half way between the charges.
Now;
Ue = Kq1q2/r
K = electric field
q1 and q2 = charges
r = distance separating them
Ue = 9 * 10^9 * 10.8 * 10^-9 * 51.9 * 10^-9/(0.5)/2
Ue = 2 * 10^-5 N/C
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