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Lifting a 81-kg barbell and weights from rest up to a speed of 1.0 m/s in 0.50 s, resisted by the combined weight of the barbell and weights, requires what applied force in N to two significant digits?

Respuesta :

Answer:

960 N

Explanation:

answer should have two signif digits  

a = change in velocity divided by change in time

   1 m/s / .5 s =   2 m/s^2

F = ma      a = g + 2 m/s^2 = 9.81 + 2 =  11.81 m/s^2

  81 kg * 11.81 m/s^2   = 956.61   N = ~ 960 N  (two sig digits)

(Please let me know if this is incorrect....I am not SURE )

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