17.90 KJ of energy must be added to 69. 0 grams of water to change the temperature from 33°C to 95°C
Specific heat, the quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree. The units of specific heat are usually calories or joules per gram per Celsius degree.
Heat added = H = mc(ΔT )
where,
H = heat
m = mass of water = 69 g
c = specific heat of water = 4.184 J/g/°C
ΔT = change in temperature
H = 69 * 4.184 * ( 95 - 33 )
H = 17899.152 J
= 17.90 KJ
To learn more about specific heat here
https://brainly.com/question/21041726
#SPJ4
