Respuesta :
There are 34 protons , 45 neutrons and 36 electrons, in that order are present in the anion formed by one atom of 79Se .
Calculation
The number of electron / protons ( present in the nucleus ) of the atom is equal to atomic number .
The sum of number of electron / protons ( present in the nucleus ) and neutrons ( present in the nucleus ) of the atom is called atomic mass.
The atomic number of Se = 34
The Mass number or atomic mass of Se = 79
The anion of Se = [tex]Se^{-2}[/tex]
It means two electron loss by Se and form [tex]Se^{-2}[/tex] .
So , the difference between number of electrons and protons = 2
Hence , number of electron and proton in [tex]Se^{-2}[/tex] anion is 34 ( two less than number of protons ) and 36
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