A solution of acetic acid , on a laboratory shelf was of undetermined concentration. if the pH of the solution was found to be 2. 68 , then its the concentration of the acetic acid was 2×[tex]10^{-3}[/tex]
Calculation ,
A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.
We have to find concentration of the acetic acid .
pH = 2. 68
pH = -㏒[ [tex]H^{+}[/tex] ]
2. 68 = -㏒[ [tex]H^{+}[/tex] ]
[ [tex]H^{+}[/tex] ] = [tex]10^{-2.68}[/tex]
[ [tex]H^{+}[/tex] ] = 2×[tex]10^{-3}[/tex]
To learn more about acetic acid please click here ,
brainly.com/question/15202177
#SPJ4
