The power required will be equal to 463.3 watt
Power is defined as the rate of work
[tex]P=\frac{W}{t}[/tex]
here P is power , W is work done , t is time taken
work done is defined as force times displacement
here s is displacement
here total force will be the weight of the firefighter plus the weight of gear
therefore F=(90+40)×9.8 N
so substituting value in equation of power we get
P=[tex]\frac{25480}{55}[/tex]
p=463.3 watt
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