Hydration number is 9
Given:
molar mass of na2so4•nh2o = 304.04 g/mol
To Find:
hydration number 'n'
Solution: hydration number is the number of molecules of water with which an ion can combine in an aqueous solution of given concentration.
Atomic mass of Na = 23g
S = 32g
0 = 16g
H = 1g
Molar mass of the compound is evaluated as:
2(23) +32 + 4(16) + n[2(1) +16] = 304.04
46 +32 +64 +18n = 304.04
142 +18n = 304.04
18n = 304.04 - 142
18n = 162.04
n = 9
So, hydration number is 9
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