If an electron falls from the n = 2 to the n = 1 energy levels in a Hydrogen atom what wavelength of light is emitted?
Group of answer choices

A. 122 nm

B. 1024 nm

C. 97 nm

D. 103 nm

We know that from the Bohr model of the atom, an electron can move from a higher energy level to a lower energy level or from a lower energy level to a higher energy level. This is the idea of energy quantization as put forward by Neill Bohr.

The wavelength can be obtained by the use of the formula;

1/λ = RH(1/n^2initial - 1/n^2 final)

λ = wavelength of the emitted light

RH = Rydberg's constant

n intial = initial energy level

nfinal = final energy level

Thus;

1/λ = 1.09 * 10^7(1/1^2 - 1/2^2)

1/λ = 1.09 * 10^7( 1 - 0.25)

λ = 122 nm

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If an electron falls from the n = 2 to the n = 1 energy levels in a Hydrogen atom what wavelength of light is emitted? Group of answer choices A. 122 nm B. 1024 nm C. 97 nm D. 103 nm

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What is the wavelength?

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If an electron falls from the n = 2 to the n = 1 energy levels in a Hydrogen atom what wavelength of light is emitted?
Group of answer choices

A. 122 nm

B. 1024 nm

C. 97 nm

D. 103 nm