Respuesta :
The mass (g) of a piece of magnesium wire that produces 41. 8 ml of hydrogen gas collected over water at 21. 0 °c and at a pressure of 752 torr is 0.041 gm.
Calculation,
According to ideal gas equation,
PV = nRT
Where, P is the pressure = 752 torr = 752 mmHg/760 mmHg/atm
P is the pressure in atm = 0.989atm
V is the volume = 41. 8 ml = 0.0418 L
R is the universal gas constant = 0.0821 Latm/mol K
T is the temperature = 21. 0 °C = 21. 0 + 273 = 294 K
n is the number of moles = ?
By putting value of P , V , T , and R in equation (i) we get,
0.989atm × 0.0418 L = n ×0.0821 Latm/mol K ×294 K
n = 0.989atm × 0.0418 L/0.0821 Latm/mol K×294 K = 0.00171 mol
Number of moles (n) = given mass/ molar mass = given mass/24.305
Mass = Number of moles×molar mass = 0.00171 mol×24.305 g/mol
Mass of the magnesium wire = 0.041 gm
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