The elementary row operation that will reduce the x–element in row 2 to 0 in this matrix is -2R1 + R2
How to determine the elementary row operation?
The complete question is added as an attachment
The matrix is given as:
1 1 1 12
2 1 0 14
2 0 3 19
Rewrite as:
x y z
1 1 1 12
2 1 0 14
2 0 3 19
So, the x-element of the second row is
x = 2
When the first row is multiplied by negative 2 and added to the second row, the x-element of the second row is reduced to 0
This is represented as;
-2R1 + R2
i.e.
-2(1 1 1 12)
+ 2 1 0 14
---------------------------
0 -1 -2 -10
Hence, the elementary row operation that will reduce the x–element in row 2 to 0 in this matrix is -2R1 + R2
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