Respuesta :
The standard free energy change ΔG° at 600 K is equal to 1. 4×[tex]10^5[/tex]J/mol then the equilibrium constant at 600K is 0 .
Calculation ,
ΔG° = - RT㏑Kp
Where ΔG° = standard free energy change = 1. 4×[tex]10^5[/tex]J/mol
R = universal gas constant = 8.3 J / K mol
T = temperature = 600K
Kp = equilibrium constant
Now putting the value of all data in equation (i) we get ,
1. 4×[tex]10^5[/tex]J/mol = - 8.3 J / K mol × 600K ㏑Kp
- 1. 4×[tex]10^5[/tex]J/mol /8.3 J / K mol × 600K = ㏑Kp
㏑Kp = - 6972×[tex]10^5[/tex]
Kp = 0
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