A population of 200 mice contains 168 brown mice. brown is dominant to gray. how much of the population would be heterozygous?

Heterozygous refers to the presence of two different allele types for the same gene. For a single gene, these alleles display two distinct character types. An illustration would be someone with an allele for both brown and black hair.

There are 200 mice in total, 168 of which are brown.

By the Hardy–Weinberg (HW) equilibrium

q² (bb) = (200 - 168) /200 = 32 / 200 = 0.16

q: √ 0.16 = 0.4

p = 1 - q = 1 - 0.4 = 0.6

p² (BB) = 0.6 x 0.6 = 0.36

Thus, 84% of the population of mice would be heterozygous.

What is meant by population heterozygosity?

Given that q2 is significantly smaller than 2pq when q is close to zero and p2 is significantly smaller than 2pq when p is close to zero, rare alleles are mostly found in heterozygotes.
This is known as population heterozygosity.

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