⟨A = 7•x + 40° and ⟨B = 3•x + 112°
From a possible diagram of the question, ⟨A = ⟨B, which gives;
Given;
⟨A = 7•x + 40°
⟨B = 3•x + 112°
In the diagram from a similar question posted online, we have;
Corresponding angles formed by parallel lines having a common transversal are congruent, therefore;
Which gives;
7•x + 40° = 3•x + 112°
7•x - 3•x = 112° - 40° = 72°
7•x - 3•x = 4•x = 72°
x = 72° ÷ 4 = 18°
Therefore;
Which gives;
⟨A = 7•x + 40°
⟨A = 7 × 18 + 40° = 166°
Learn more about angles formed by parallel lines that have a common transversal here:
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