He heat of solution of kcl is 17. 2 kj/mol and the lattice energy of kcl(s) is 701. 2 kj/mol. calculate the total heat of hydration of 1. 00 mol of gas phase k ions and cl– ions

Respuesta :

The total heat of hydration of 1. 00 mol of gas phase [tex]K^{+}[/tex] ions and [tex]Cl^{-}[/tex]ions is - 684 kJ/mol.

Calculation ,

Given data ,

Heat of solution =  17. 2 kJ/mol

lattice energy of KCl(s) = 701. 2 kJ/mol.

heat of hydration = ?

The KCl is formed by[tex]K^{+}[/tex] ions and [tex]Cl^{-}[/tex]– ions

Δ[tex]H_{solution}[/tex] = U° + Δ[tex]H_{hydration}[/tex]

Δ[tex]H_{hydration}[/tex] = Δ[tex]H_{solution}[/tex] - U° =  17. 2 kJ/mol - 701. 2 kJ/mol = - 684 kJ/mol

Hence, heat of hydration of 1. 00 mol of gas phase [tex]K^{+}[/tex] ions and [tex]Cl^{-}[/tex] ions is - 684 kJ/mol.

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