The x-intercept of the function g(x) = -5(x - 3)^2 is (3, 0) and the vertex of the function g(x) = -5(x - 3)^2 is (3, 0)
The function is given as:
g(x) = -5(x - 3)^2
Set g(x) to 0, to determine the x-intercept.
-5(x - 3)^2 = 0
Divide through by -5
(x - 3)^2 = 0
Take the square root of both sides
x - 3 = 0
Add 3 to both sides
x = 3
Hence, the x-intercept of the function g(x) = -5(x - 3)^2 is (3, 0)
The function is given as:
g(x) = -5(x - 3)^2
A quadratic function is represented as:
g(x) = a(x - h)^2 + k
Where, the vertex is
Vertex = (h, k)
By comparing g(x) = a(x - h)^2 + k and g(x) = -5(x - 3)^2, we have
(h, k) = (3, 0)
Hence, the vertex of the function g(x) = -5(x - 3)^2 is (3, 0)
Read more about x-intercept and vertex at
https://brainly.com/question/1305604
#SPJ1
