The sum of all five numbers in the list is 25.
According to the question,
The first number on my list of five numbers is 1, and the fifth is 5. The other figures are all one more than their two nearest neighbors' averages.
Let the list of numbers be 1,x,y,z,5.
As each of the other numbers is equal to one more than the average of its two neighbors.
x=(1+y)/2+1
2x=3+y -(1)
Similarly,
y=(x+z)/2+1
2y=x+z+2 -(2)
z=(y+5)/2+1
2z=y+7 -(3)
Multiply equation (2) by 2 and then substitute equations (1) and (3),
4y=3+y+y+7+4
4y=2y+14
2y=14
y=14/2
y=7
From equation (1),
2x=3+7
2x=10
x=5
From equation (3),
2z=7+7
2z=14
z=14/2
z=7
The list is: 1,5,7,7,5
Sum of the numbers of list = 1+5+7+7+5 = 25
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