The pH of a 0.250m solution of succinic acid is 2.42.
Succinic acid is one of the naturally occurring dicarboxylic acid having four carbon, which is produced by LPG.
It can be used in many chemical, food, and pharmaceutical industries.
Given,
pKa = 4.21
As we know that,
pKa = - logKa
4.21 = -logKa
Ka = antilog(-4.21)
Ka = 6.1 × 10^(-5)
Now, let the concentration of [H+] = [A-] = x
Ka = [H+] [A-] /[HA]
6.1 × 10^(-5) = x^2/ (0.25-x)
x^2 = 1.52 × 10^(-5)
x = 3.89 × 10^(-3)
Thus, the concentration of [H+] = [A-] = 3.89 × 10^(-3).
Now, we will calculate the value of pH
pH = - log[H+]
pH = -log(3.89 × 10^(-3))
pH = 2.42
Thus, we found that the pH of the given solution is 2.42.
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