The distance between two slits is d =2.89*10^-7 m
Distance between slits, d=2.89*10^-7 m
It is given that,
Wavelength, λ = 410nm= 410*10^-9 m
Angle, θ =45
We need to find the distance between two slits that produces first minimum. The equation for the destructive interference is given by :
dsinθ =(n+1/2) λ
For first minimum, n = 0
dsinθ =(1/2) λ
So, d is the distance between slits
d ={1/2 λ}sinθ
=2.89*10^-7 m
So, the distance between two slits is d =2.89*10^-7 m. Hence, this is the required solution.
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