A 1. 7 m solution of the acid ha has a ph of 1. 0, then the ka of the acid is 6.25×10^(-3).
The acid dissociation constant is defined as the value which is used to measure the strength of the specific acid in the solution.
Equation for general dissociation of strong or weak acid is
HA ----- (H+) + ( A-)
Ka can be expressed as
Ka = [H+] [A-]/[HA]
where [H+] is the concentration of H+ ions
Now, we will find the value of concentration of H+ ions
pH = -log [H+]
1 = -log[H+]
[H+] = antilog(-1)
[H+] = 0.1
By using ICE table, we find that the concentration of [HA] is
1.7-0.1
= 1.6
By substituting all the values we get,
Ka = 0.1 × 0.1/1.6
= 6.25×10^(-3)
Thus, we find that the Ka value of the given solution is 6.25×10^(-3).
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