When mixture of H2PO4- and OH- is allowed to react. The products of the reaction are as follow
H2PO4+ OH--------HPO4(2-)+H2O
In the reaction above H2PO4(2-) is donating the proton to OH Resulting in H2O and the deprotonated species. This makes it a bronsted lowry acid.
According to Bronsted lowry, acid are those which donate proton.
In the given problem, H2PO4- is bronsted lowry acid. So it donate electron to OH- to form water.
Thus, the product formed in the given reaction is water and H2PO4(2-).
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