The distance between slit and the screen is 1.214m.
To find the answer, we have to know about the width of the central maximum.
[tex]w=\frac{2*wavelength*d}{a}[/tex]
where, d is the distance between slit and the screen, and a is the slit width.
[tex]d=\frac{w*a}{2*wavelength} =\frac{8*10^{-3}*0.17*10^{-3}}{560*10^{-9}*2} \\\\d=1.214m[/tex]
Thus, we can conclude that, the distance between slit and the screen is 1.214m.
Learn more about the width of the central maximum here:
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