Carbon atoms present in 2. 00 g of butane is 8.28 × 10^22.
Molecular weight of C4H10 is = 58.1 grams
Moles of butane = given mass/ molar mass
= 2/58.1
= 0.0344 mol
Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:
0.0344 x 6.023 x 10^{23} molecules of butane = 2.07 × 10^22 molecules
of butane
Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the answer:
so, no. of carbon atoms = 4 x 2.07x 10^22 = 8.28x 10^22 atoms.
Thus the no. of carbon atom is 8.28×10^22.
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