The solution of the equation is (2, 1).
x=2 and y=1
A mathematical assertion that two expressions are equal is known as equating. It can be expressed as either an identity, in which case the variables can take on any value, or a conditional equation, in which case the variables can only have specific values (roots).
We have two options for finding the answer. The first is to solve the equations via term elimination:
x + 3y = 5 ..............1
x - 3y = -1 ...............2
2x = 4 ..............3
With the equation, we can determine x. (3)
x = 4/2
x = 2
To determine y, we may now swap out x=2 in equation (1).
x + 3y = 5
2 + 3y = 5
3y = 3
y = 1
We've discovered x and y now.
x=2
y=1
The second method involves removing x from equation 1.
x + 3y = 5
x = 5 - 3y
In the equation right now, we may substitute x = 5 - 3y......... (2)
x - 3y = -1
(5 - 3y) - 3y = -1
5 - 6y = -1
6y = -6
y = 1
Currently, we can change y=1 in equations (1), (2), or (4) to find x.
We'll apply the equation (1)
x + 3y = 5
x + 3(1) = 5
x + 3 = 5
x = 2
The two variants x = 2 and y = 1 have allowed us to confirm this.
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