Respuesta :
Correct option is C
Latent heat of vaporization is the amount of heat required to bring about the phase transition from liquid to gaseous state, at its boiling point.
The substance is Propane :
10140000 J of heat is used to boil 28.47 kg at 298 K. Here, the important thing is, the liquid is changing to vapor and the temperature is not changing means it's a phase change. So, the formula used for this is:
q=m× Δ[tex]H_{vap}[/tex]
where, q is the heat energy, m is mass and Δ[tex]H_{vapour}[/tex] is the enthalpy of vaporization.
Let's rearrange the formula for as:
Given mass of the liquid = 28.47kg
Heat required to boil the liquid = 10.14 ×[tex]10^{2} J[/tex]
Let's plug in the values: [tex]\frac{10.14*10^{2}J }{28.47Kg} =356164\frac{J}{Kg}[/tex]
Rounding off 356164 will turn into 356000 J[tex]Kg^{-1}[/tex]
Hence, the right choice is C. propane 356000 j[tex]Kg^{-1}[/tex]
What is latent heat ?
Latent heat, energy absorbed or released by a substance during a change in its physical state (phase) that occurs without changing its temperature.
Learn more about latent heat of vaporization :
brainly.com/question/24203857
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