The resulting value of the function when the values of t is 2 and 6 are 3.5 and 6.5 respectively
Function and values
Functions are expressions in form of variables. Given the following quadratic equation expressed as:
f(t) = 0.25t^2 − 0.5t + 3.5
We can find the equivalent value of the function when the value of t a re 2 and 6.
If the value of t is 2. hence;
f(2) = 0.25(2)^2 − 0.5(2) + 3.5
f(2) = 1 - 1 + 3.5
f(2) = 3.5
If the value of t is 6, hence;
f(6) = 0.25(6)^2 − 0.5(6) + 3.5
f(6) = 9 - 3 + 3.5
f(6) = 6.5
Hence the resulting value of the function when the values of t is 2 and 6 are 3.5 and 6.5 respectively
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