The acid dissociation constant of a weak monoprotic acid if the concentration of the acid is 0.3M and it has a pH of 3 is 3 × 10⁻⁶.
The acid dissociation constant (Ka) is the equilibrium constant for an acid dissociation reaction.
Let's consider the acid dissociation of a generic weak acid.
HA(aq) = H⁺(aq) + A⁻(aq)
The pH of the solution is 3.
pH = -log [H⁺]
[H⁺] = antilog -pH = antilog -3 = 1 × 10⁻³ M
The concentration of the acid (Ca) is 0.3 M. For a weak monoprotic acid, we can calculate the acid dissociation constant using the following expression.
[H⁺] = √(Ca × Ka)
Ka = [H⁺]² / Ca
Ka = (1 × 10⁻³)² / 0.3 = 3 × 10⁻⁶
The acid dissociation constant of a weak monoprotic acid if the concentration of the acid is 0.3M and it has a pH of 3 is 3 × 10⁻⁶.
Learn more about weak acids here: https://brainly.com/question/15192126
#SPJ1