Solve the system using substitution. 2x + 2y = 38 y = x + 3
We need to solve y = x+ 3 for y substitute x + 3 for y in 2x + 2y = 38 2x + 2y = 38 Now replace x+3 everywhere there's y 2x + 2(x+3) = 38 2x + 2x + 6 = 38 4x + 6 = 38 4x = 38 - 6 4x = 32 x = 32/4 x = 8 Now, we have the number of x which is gonna help us find y what we gonna do is replace 8 everywhere we see an x so we find y. Please follow me :)
Substitute 8 for x in y = x + 3 y = 8 + 3 y = 11 Final answer : x = 8 and y = 11 The correct option is A
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