How much energy is required to heat 36. 0 g h2o from a liquid at 65°c to a gas at 115°c? the following physical data may be useful.

Respuesta :

The required energy will be "87752 J".

What is energy?

The definition of energy is "ability to do work," which is the capacity to apply a force that causes an item to move.

Mechanical, heat, chemical, electrical, radiant, nuclear, and sound are the seven types of energy.

The energy will be:

Q1 = 36 × 3.18(100-65)

Q1 = 5267 J

Moles of water = [tex]\frac{36.0}{18}[/tex]

Moles of water = 2

then,

Q2 = 2× 40.7

Q2 = 81.4 KJ

Q2 = 81400 J

Q3 = 36.0 × 2.01(115-100)

Q3 = 1085 J

hence,

Required energy will be= Q1+ Q2+ Q3

Required energy = 5267 + 81400 + 1085

Required energy = 87752 J

hence, 87752 J energy is required to heat 36. 0 g h2o from a liquid at 65°c to gas at 115°c.

To learn more about energy calculation refer to:  https://brainly.com/question/14121237

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