26.676 × 10³ kg is the weight of the aluminum rod.
Given:
Length of cylindrical rod (h) = 45 cm
Diameter of a cylindrical rod = 4.53 cm
Radius of a cylindrical rod (r) = 2.3 cm
The density = 3.7*10^3kg/m^3
Volume of a cylindrical rod = πr²h
= 3.14× (2.3)² × 45
= 747.89 cm
= 7.4789 m
To find weight ;
ρ = [tex]\frac{Mass}{Volume}[/tex] ; ρ = Density
Mass = ρ × Volume
= 3.7 × 7.48 × 10³
=27.676 × 10³ kg
Therefore, the weight of the aluminum rod is 27.676 × 10³ kg.
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