ΔDGC is right because Line E G is perpendicular-to CC', Option D is the correct answer.
Reflection along a line is plotting a new object as a mirror image of the original object .
It is given that the there are two Triangles , ABC and A'B'C' as an image.
The figure is attached with the answer.
D is the mid point of the line joining BB'
As the line of reflection is always perpendicular to the object and the image.
And as it is given that C G F is a right angle.
Therefore triangle DGC is right angled triangle , (the option given in the question is incorrect ) , Line E G is perpendicular-to CC'.
Option D is the correct answer.
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