Step-by-step explanation:
Let x be mixture x liters and y be mixture y liters.
We need a total of 4 liters so
[tex]x + y = 4[/tex]
Mixture x is 20% saline solution
Mixture Y is a 10% saline solution
4 liters of a 15% saline solution is 60% saline solution.
[tex].20x + .10y = 0.6[/tex]
So a is the system of equations,
Using Elimination, eliminate the variable x.
[tex] - 5(.20x + .10y) = 0.6[/tex]
[tex]( - x - .50y) = - 3[/tex]
Add to the first system.
[tex]0.50y = 1[/tex]
[tex]y = 2[/tex]
Plug this into the of system of equations, to find x
[tex]x + 2 = 4[/tex]
[tex]x = 2[/tex]
So our solution is (2,2) We would need 2 liters of Mixture X and 2 liters of Mixture Y
