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Use the Factor Theorem to determine whether x + 1 is a factor of P(x) = 2x³+4x²–2x−8.
Specifically, evaluate P at the proper value, and then determine whether x + 1 is a factor.

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rdacoder

Answer: [tex]2x^2+2x-4-\frac{4}{x+1}[/tex]

Not a factor because there is a remainder.

Step-by-step explanation:

Let's use synthetic division to solve this..

-1  ║ 2 | 4 | -2 | -8

   ║    | -2| -2 |  4

   ║ 2 | 2|  -4 |  -4

[tex]2x^2+2x-4-\frac{4}{x+1}[/tex]

PS: if anyone knows a better way to do a synthetic division chart please let me know.

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