The mass of NO produced is 9.3 g; option D.
The mass of nitrogen (ii) oxide, NO, produced from the reaction is determined from the mole ratio of the reaction.
The mole ratio of ammonia to oxygen from the equation of the reaction is 4 : 5.
moles of oxygen = 11.8/32 = 0.368
moles of ammonia = 8.3/17 = 0.488
Oxygen is the limiting reactant.
Mass of NO produced = 0.369 * 4/5 * 30 = 9.4 g NO
In conclusion, approximately 9.3 g of NO is produced.
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