Using it's concept, it is found that there is a 0.1541 = 15.41% probability that the first three balls are drawn out of the box alternated in colour.
What is a probability?
A probability is given by the number of desired outcomes divided by the number of total outcomes.
Considering the situation described, the ways that alternate colored balls can be taken with the probabilities given as follows:
- R(5/8) - W(3/9) - R(5/11).
- W(3/8) - R(5/10) - W(5/11).
Hence the probability that the first three balls are drawn out of the box alternated in colour is given by:
[tex]p = \frac{5}{8} \times \frac{3}{9} \times \frac{5}{11} + \frac{3}{8} \times \frac{5}{10} \times \frac{5}{11} = 0.0689 + 0.0852 = 0.1541[/tex].
0.1541 = 15.41% probability that the first three balls are drawn out of the box alternated in colour.
More can be learned about probabilities at https://brainly.com/question/14398287
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