The amount of the investment at the end of the 10 years period if compounded quarterly is $2,649.6.
A = P(1 + r/n)^nt
= 1200(1 + 0.08/4)^(4×10)
= 1200(1 + 0.02)^40
= 1200(1.02)^40
= 1200(2.208)
= $2,649.6
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