Answer:
147
Step-by-step explanation:
[tex]\displaystyle \frac{f(b)-f(a)}{b-a}\\ \\\frac{f(5)-f(3)}{5-3}\\ \\\frac{(3(5)^3+2)-(3(3)^3+2)}{2}\\ \\\frac{(3(125)+2)-(3(27)+2)}{2}\\ \\\frac{(375+2)-(81+2)}{2}\\ \\\frac{377-83}{2}\\ \\\frac{294}{2}\\ \\147[/tex]
Recall that if a function [tex]f[/tex] is continuous over the interval [tex][a,b][/tex], then its average rate of change is [tex]\frac{f(b)-f(a)}{b-a}[/tex].
