Answer :]
This is an oxidation-reduction (redox) reaction:
S0 + 2 e- → S-II (reduction)
2 K0 - 2 e- → 2 KI (oxidation)
S is an oxidizing agent, K is a reducing agent.
Answer:
K
Explanation:
Here, in this reaction 2 moles of potassium react with 1 mole of sulfur to form 1 mole of potassium sulfide.
Let's compare the electronic configurations of both elements :
⇒ K = {2, 8, 8, 1}
⇒ K can attain noble gas configuration by losing one electron
⇒ K exists as : K⁺
⇒ S = {2, 8, 6}
⇒ S can attain noble gas configuration by the addition of 2 electrons
⇒ S exists as S²⁻
Now, we know that will lose protons when oxidized. Hence, here the substance which is oxidized is K
