The probability of 3 successes is 0.0384
How to determine the probability?
The given parameters are:
- Trials, n = 4
- Probability of success, p = 0.4
The binomial probability is represented as:
[tex]P(x) = ^nC_x * p^x * (1 - p)^{n-x[/tex]
So, the probability of three successes is:
[tex]P(3) = ^4C_3 * 0.4^3 * (1 - 0.4)^{4 -3[/tex]
Evaluate the factors in the expression
[tex]P(3) = ^4C_3 * 0.0384[/tex]
Evaluate the combination expression
P(3) = 1 * 0.0384
Evaluate the product
P(3) = 0.0384
Hence, the probability of 3 successes is 0.0384
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