Based on the calculations, the acceleration of this block as it slides down from the friction less ramp is equal to 0.85 m/s².
In order to determine the acceleration of this block, we would apply Newton's Second Law of Motion while taking moment about the tensional force.
The vertical component of the tensional force that is acting on the block as it slides down from this friction less ramp is given by:
T = Ma - Mgsinθ
0 = Ma - Mgsinθ
Ma = Mgsinθ
a = gsinθ
Substituting the given parameters into the formula, we have;
a = 9.8 × sin25
a = 9.8 × 0.4226
Acceleration, a = 0.85 m/s².
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