Respuesta :
Work done
- FscosØ
- 208.4(161.5)cos32
- 33656.6cos32
- 28542.4J
Work done by kinetic friction:-
- [tex]\mu_kN[/tex]
- [tex]\sf \mu_Kmg[/tex]
- 0.455(197)(9.8)
- 878.423N
Answer:
The Work done is 28542.4J.
The work done by the kinetic friction is 878.423N
Given:
FscosØ
We put the values together.
208.4(161.5)cos32
33656.6cos32
28542.4J
Work done by kinetic friction:-
Given the formula, we put the values.
0.455(197)(9.8)
878.423N