The value of the constant a will the system of linear equations 6x-5y=3 and 3x+ay=1 have no solution is -5/2
For a system of equation to have no solution, the expression on both sides must be different.
Given the system of equation
6x-5y=3 and
3x+ay=1
For the equations to have no solution, the a1/a2= b1/b2
Substitute
6/3 = -5/a
Cross multiply
2 = -5/a
a= -5/2
Hence the value of the constant a will the system of linear equations 6x-5y=3 and 3x+ay=1 have no solution is -5/2
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