For problem 17, if you double the diameter of the moon, then the surface increases by a factor of 4 and the volume by a factor of 8.
Let's answer question 17.
Remember that for a sphere of radius R, the volume is:
[tex]V = (4/3)*pi*R^3[/tex]
And the surface area is:
[tex]S = 4*pi*R^2[/tex]
So the volume depends on the cube of the radius and the surface on the square of the radius.
Now, if we double the diameter of the moon, then we also double the radius.
So the new volume will be:
[tex]V' = (4/3)*pi*(2*R)^3 = 8*[(4/3)*pi*R^3] = 8*V[/tex]
The new volume is 8 times the original volume.
And for the surface:
[tex]S' = 4*pi*(2*R)^2 = 4*[4*pi*R^2] = 4*S[/tex]
So the new surface is 4 times the original surface.
If you want to learn more about spheres:
https://brainly.com/question/10171109
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