The time needed to evaporate all the water in the kettle is 1.13 x 10³s.
The power is defined as the the ratio of amount of energy produced per unit time.
P =E/t
Energy is in the form of heat gained to evaporate all water in kettle.
E = Q =mL
So, P = mL/t
Substitute mass of water m = 0.5kg, latent heat of vaporization of wate L = 2.26 x 10⁶ J/kg, power P= 10³ W, we have
10³ = (0.5 x 2.26 x 10⁶) /t
t = 1.13 x 10³s
Thus, the time needed to evaporate all the water is 1.13 x 10³s.
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