The net ionic equation for Lead 2 acetate and ammonia would be written as follows:
(CH3COO)2Pb (aq) + (NH4)2SO4 (aq) --> 2CH3COONH4 (aq) + PbSO4 (s)
Ionic eq: 2CH3COO^- (aq) + Pb^2+ (aq) + 2NH4^+ (aq) + SO4^2- (aq) --> 2CH3COO^- (aq) + 2NH4^+ (aq) + PbSO4 (s)
Spectator ions: CH3COO^-, NH4^+
Pb^2+ + SO4^2- --> PbSO4 (s)