marl333n
marl333n marl333n
  • 04-05-2022
  • Mathematics
contestada

in need of help please :)

in need of help please class=

Respuesta :

kalulesultan
kalulesultan kalulesultan
  • 04-05-2022

Answer:

okay let's start

Step-by-step explanation:

[tex]number \: 1 \\ cos \: b = \frac{adjacent}{hypotenuse} \\ cos \: b = \frac{ac}{cb} \\ \: \ cos \: b = \frac{12}{13} \\ [/tex]

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